The osmotic pressure, π, of a solution of glucose is 83.1 atm . find the molarity of the solution at 298 k. express the molarity to three significant figures and include the appropriate units.

Molarity for this solution is: 3.40 mol/L

Explanation:

Osmotic pressure is the colligative property which formula is:

π = M . R . T

83.1 atm = M . 0.082 L.atm/mol.K . 298K

83.1 atm / (0.082 L.atm/mol.K . 298K) = M

As you see all the units are cancelled, except for mol/L which means certainly Molarity

83.1 atm / (0.082 L.atm/mol.K . 298K) = 3.40 mol/L

the seeing the electronic configuration we can say that the element is fluorine.

fluorine is the most electronegative element in the periodic table.

but by only seeing the configuration we cannot say about its reactivity because we don't know if its configuration after excitation or by addition of electrons.

but if not then, it is the lightest halogen and exists as a highly toxic pale yellow diatomic gas at standard conditions. as the most electronegative element, it is extremely reactive: almost all other elements, including some noble gases, form compounds with fluorine.