8oz bottle of dr. pepper made with imperial cane sugar (c12h22o11) contains 27 g of sugar in 236.6 ml of water. what is the molarity of the solution with respect to cane sugar?

0.33M

Explanation:

Molarity is asking, in Laymens terms:

"If I took a litre of this stuff, how much stuff is gonna be in it?"

Diving deeper, we use litres instead of millilitres or nanolitres because that's usually what we're working with. We use moles rather than mass because mass varies; different substances have different molar masses, so describing something in g/L makes no sense if you're comparing two different solutions.

Anyway, go find the number of moles:

n=m/mm

n=27g/342.34g/mol

n=0.078870mol

The next question you've gotta ask yourself is:

What if I had a litre of it?

V = 0.2366L

M=n/V

M=0.078870mol/0.2366L

M=0.33M

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol

the right answer is c i just did the question.