How much energy must be removed from a 125 g sample of benzene (molar mass= 78.11 g/mol) at 425.0 k to liquify the sample and lower the temperature to 335.0 k? the following physical data may be useful.

hvap = 33.9 kj/molhfus = 9.8 kj/mol
cliq = 1.73 j/g

Answer : The energy removed must be, -34.67 kJ

Solution :

The process involved in this problem are :

The expression used will be:

where,

= heat available for the reaction =

m = mass of benzene = 125 g

= specific heat of solid benzene =

= specific heat of liquid benzene =

= enthalpy change for fusion =

Molar mass of benzene = 78 g/mole

Now put all the given values in the above expression, we get:

Therefore, the energy removed must be, -34.67 kJ

i think slash and

the answer is b. dilution