Consider the reaction of ethyl bromide with sodium hydroxide: [tex]ch_3ch_2br(aq) + naoh(aq) ightleftharpoons ch_3ch_2oh(aq) + nabr(aq)[/tex]the reaction is first order in naoh and second order overall. what is the rate law?

rate law = K [CH3CH2BR] [NaOH]Explanation:What is applied here is the principle of rate of reaction ...

Chemistry, 29.01.2020 03:45 20heldmadison

Consider the reaction of ethyl bromide with sodium hydroxide: $ch_3ch_2br(aq) + naoh(aq) \rightleftharpoons ch_3ch_2oh(aq) + nabr(aq)$ the reaction is first order in naoh and second order overall. what is the rate law?

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Consider the reaction of ethyl bromide with sodium hydroxide: [tex]ch_3ch_2br(aq) + naoh(aq) \right...