Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas         Mole Fraction      kH mol/(L*atm)

           Ar                                  

The solubility of hydrogen gas in water at given atmospheric pressure is

Explanation:

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

where,

= partial pressure of hydrogen gas = ?

= total pressure = 0.380 atm

= mole fraction of hydrogen gas =

Putting values in above equation, we get:

To calculate the molar solubility, we use the equation given by Henry's law, which is:

where,

= Henry's constant =

= partial pressure of hydrogen gas =

Putting values in above equation, we get:

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

56 moles of   lieter in chemistry