If you have 2.41 × 1024 atoms of copper, how many moles of copper do you have? if you have 2.41 atoms of copper, how many moles of copper do you have? 4.00 0.600 3.00 0.250 none of the above

4.00 moles

Explanation:

Avogadro´s number is 6.022 x 10²³ molecules, atoms, particles, etc.

Here we are talking of atoms of copper, so 1 mol of copper is equal to 6.022 x 10²³ atoms, and we only need to setup the proportion to find the number of mol in 2.41 x 10²⁴ atoms. ( Think of it like a dozen, avogadro´s is 6.022 x 10²³ )

( 1 mol copper/ 6.022 x 10²³ atoms of copper ) x  2.41 x 10²⁴ atoms

= 4.00 moles

calculate how many grams of ammonia can be produced from 4.21 grams of

n2 + 3h2 = 2nh3

my answer:

25.0g n2 x (1 mol/ 28.0gn2) x (2 mol nh3/ 1 mol n2) x (17.0g nh3/ 1 molnh3) = 30.36g n2

25.0g h2 x (1 mol h2/ 2.00g h2) x (2 mol nh3/ 3 mol h2) x (17.0g nh3/ 1 mol nh3) = 141.67g h2

lr = n2

it would be d. henry moseley

hope this !

and sorry if i'm late. have a good rest of your day! : d