At particular temperature, kp = 70.9 for the following reactionn2o4(g) == 2no2(g)1. a certain pressure of n2o4 is initially added to an otherwise evacuated.2. at equilibrium, 25.8% of n2o4 remains.3. what is the partial pressure of no2 at equilibrium?

Answer : The partial pressure of is, 12.34  atm

Explanation :

For the given chemical reaction:

The expression of for above reaction follows:

        ........(1)

The equilibrium reaction is:

Initial             x                    0

At eqm       (x-y)                 2y

Putting values in expression 1, we get:

          ..............(2)

As we are given that, 25.8 % of remains at equilibrium. That means,

      ..............(3)

Now put equation 3 in 2, we get the value of 'x'.

Now put the value of 'x' in equation 3, we get:

Now we have to calculate the new partial pressure of at equilibrium.

Partial pressure of = (2y) = (2\times 6.17) = 12.34  atm

Hence, the partial pressure of is, 12.34  atm