Achemistry student needs 45.00g of 4-methyl-2-pentanone for an experiment. he has available 0.50 kg of a 10.9% w/w solution of 4-methyl-2-pentanone in acetone. calculate the mass of solution the student should use.

                    0.412 Kg of Solution

Explanation:

                    To solve this problem we will first find the number of grams of solute contained by the given amount of solution as,

                      w/w%  =  weight of solute / weight of solution × 100

Solving for weight of solute,

                      Weight of solute = w/w% × weight of solution / 100

Putting values,

                      Weight of solute = 10.9 × 500 g / 100

                       Weight of solute = 54.5 g

Hence,

                  54.5 g of solute was contained by  =  500 g of solution

So,

               45.0 g of solute will be contained by  =  X g of solution

Solving for X,

                     X =  45.0 g × 500 g / 54.5 g

                      X =  412.84 g

Or,

                     X  =  0.412 Kg of Solution

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

  the   balanced   equation   for   reaction of   ca metal   with   o2 to   produce   cao   is as below

2 ca+ o2→ 2 cao2

  explanation

the reaction is   balanced     since the   number of atoms   in reactant side is   equal to   number of atoms   in   product side.   for   example   they   are 2   atom of   ca in   reactant   side   and   2   atoms of ca   in   the product side.

  the   process   is a   meet the   requirement   of   redox   reaction because :     calcium   is   oxidized   from   oxidation state 0   to 2+   while   oxygen   is reduced from   oxidation   state   0   to 2-