Given the reaction: 4nh3 +5o2 > 4no +6h2o

when 1.20 mole of ammonia reacts, the total number of moles of products formed is:

a. 1.20

b. 1.50

c. 1.80

d. 3.00

e.12.o

3 moles are produced with the reaction of 1.20 mol of NH₃  (Option 3)

Explanation:

The reaction is:

4NH₃  +  5O₂  ⇒  4NO  + 6H₂O

Therefore, 4 moles of ammonia react with 5 moles of oxygen, to produce 4 moles of nitrogen monoxide and 6 moles of water.

Ratio is 4:4 with NO and 4:6 with water.

1.20 mol of ammonia, would produce the same amount of NO and

(1.20 . 6) / 4 = 1.8 moles of water

Sum of moles of products formed is:

1.2 + 1.8 = 3 moles

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890