Binary compound created by reaction of an unknown element e and sulfur contains 27.52% e and 72.48% s by mass. if the formula of the compound is e4s10, calculate the atomic mass of e.

Answer : The atomic mass of E is, 30.4 g/mol

Explanation :

If percentage are given then we are taking total mass is 100 grams.

So, the mass of each element is equal to the percentage given.

Mass of E = 27.52 g

Mass of S = 72.48 g

First we have to calculate the moles of sulfur.

Moles of S =

Now we have to calculate the moles of E by comparing the stoichiometry of the compound.

The given compound formula is,

As, 10 moles of sulfur combine with 4 moles of E

So, 2.265 moles of sulfur combine with moles of E

Thus, the moles of E is, 0.906 moles.

Now we have to calculate the atomic mass of E.

Atomic mass of E =

Thus, the atomic mass of E is, 30.4 g/mol

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.