An empty beaker weighs 49.03 g. when completely filled with water, the beaker and its contents have a total mass of 267.05 g. what volume does the beaker hold? use d = 1.00 g/ml as the density of water.

218.02 mL

Explanation:

Data Given:

weight of the empty beaker = 49.03 g

weight of water and beaker = 267.05 g

density of water = 1 g/mL

Solution:

As we know that the volume that beaker hold is the volume of water that occupied by it.

For this first we have to find mass of the water in the beaker

This can be calculated by the subtraction of beaker's weight from the weight of beaker and water.

      weight of water (m) = total weight - weight of beaker

put values in the above formula

      weight of water (m) = 267.05 g - 49.03 g

      weight of water (m) = 218.02 g

To find volume we will use density formula

              d = m/v

rearrange the above equation to calculate volume

               v = m/d . . . . . . . (1)

put values in equation 1

            v = 218.02 g / 1 (g/mL)

            v = 218.02 mL

The volume that beaker hold = 218.02 mL

that's what i got you can count the number of atoms