Chemistry, 29.08.2019 05:30 mikecampbellashleyca

Which pair of atoms has the highest electronegativity difference?
h – s
h – cl
n – h
o – h
c – h

Answers: 1

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Answers

I'll go through them one by one
1) H-S
The electronegativity of Hydrgoen is 2.2, and sulphur is 2.58,
therefore the difference is 0.38 (2.58-2.2=0.38)
2) H-Cl
Hydrogen: 2.2, Chlorine: 3.16
therefore difference is 0.96
3) N-H
Nitrogen: 3.04, Hydrogen: 2.2
therefore difference is 0.84
4) C-H
Carbon: 2.55, hydrogen: 2.2
therefore difference is 0.35

so, the most apparent electronegativity is chlorine, but this could have been done without actually doing the maths. The trend of electronegativty increases across a period and increases up a period due to the strong affinity of the nucleus with bonding electrons. This does not include noble gases though, as they have no charge due to having complete valance shells. The most electronegative element is Fluorine (9), and the least electronegative element (besides noble gases) is Francium (87)

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

Answer from: Quest

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