Some amount of water is evaporated from a 2.0 l, 0.2 m nai solution, to from a 1.0 l solution. the molar mass of nai is 150 g/mol. what is the final concentration of nai solution in

The final concentration of NaI is 0.4M

Explanation:

Step 1: Data given

Initial volume of a 0.2 M NaI solution

To form a 1.0 L solution

The molar mass of NaI is 150 g/mol

Step 2: Calculate the moles of NaI

Moles NaI = 0.2M * 2.0 L = 0.4 moles

Step 3: Calculate the final concentration

Concentration = moles / volume

Concentration = 0.4 moles / 1.0L

Concentration = 0.4M

The final concentration of NaI is 0.4M

pv=nrt

explanation: