What is the minimum % relative error for a 0.5m naoh solution?

assume the absolute error is +/- 0.1.

20%

Explanation:

Relative error = Absolute error/actual value

= 0.1/0.5

= 0.2

Hence,

Minimum % Relative error = 0.2 ×100%

= 20%

20%

Explanation:

Let us take some important definitions of some terms in the question.

What is an ABSOLUTE ERROR?.

Absolute error is the difference between the expected value and the value you got from an experimental calculations or the approximations made. It can be represented mathematically in the equation (1) below;

Absolute error= expected value - Approximated/measured value. (1).

What is A RELATIVE ERROR?.

A relative error is the the ratio of absolute value to that of the exact value. This can be illustrated mathematically by the equation (2) below;

Relative error= absolute error/exact value. (3).

From equation (2) the solutio to the question is;

Relative error= absolute error/exact value.

Relative error=[ 0.1/0.5] = 0.2.

Relative error Percentage= 0.2×100= 20 Percent.

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is and electronic configuration of phosphorous is .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.  

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.

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