The maximum power of a small utility vehicle is 10,000 watts. at maximum power, how much time would it take for the vehicle to pull a 500 n rock 100 meters?

The time taken for the vehicle to pull a 500 N rock 100 meters is :

t = 5 sec

Explanation:

Work = The magnitude of work is given by the product of force and displacement .

W = F x s

F = Force in Newton"N"

s = displacement "s"

In the question : F = 500 N  and s = 100 m

W = F x s

W = 500 x 100

W = 50000 Nm

W = 50000 J

Power : It is the rate of doing work.The expression of power is given by :

W = Work = 50000 J

t = time

P = power = 10,000 Watt

Put the value in the formula:

t = 5 sec

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'