How many moles of mercury atoms are in 5.418 x 1023 atoms of mercury? moles

0.9 moles of Hg contain 5.418×10²³ atoms

Explanation:

As we know, Avogadro's number (NA) is the amount of particles that are contained in 1 mol → 6.02×10²³

Let's make a rule of three for this:

6.02×10²³ atoms are contained in 1 mol of Hg

5.418×10²³ atoms would be contained in (5.418×10²³ . 1) / NA = 0.9 moles

We have 0.8997 moles of mercury in 5.418 * 10^23 atoms of mercury

Explanation:

Step 1: Data given

Number of atoms of mercury = 5.418 * 10^23 atoms

Number of Avogadro = 6.022 *10^23 /mol

Step 2: Calculate number of moles of mercury

Moles mercury = number of atoms mercury / number of Avogadro

Moles mercury = 5.418 *10^23 /6.022*10^23 /mol

Moles mercury = 0.8997 moles

We have 0.8997 moles of mercury in 5.418 * 10^23 atoms of mercury

explanation:

i think option no d is the correct answer

did anyone actually do this? like if anyone has submitted this i rly need .