Fe(s) + 2hcl(aq) --> fecl2(aq) + h2(g)

when a student adds 30.0 ml of 1.00 m hcl to 0.56 g of powdered fe, a reaction occurs according to the equation above. when the reaction is complete at 273 k and 1.0 atm, which of the following is true?

a) hcl is in excess, and 0.100 mol of hcl remains unreacted.

d) 0.22 l of h2 has been produced.

the correct answer is d. i can't figure out why a is wrong.

In the option(A) moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

Explanation:

Moles of HCl = n

Molarity of HCl = 1.0M

Volume of HCl solution = 30.0 mL = 0.030 L (1 mL = 0.001L)

Moles of Fe =

According to recation , 1mol of Fe reacts with 2 mol HCl. Then 0.01 mole of Fe will recat with :

of HCl

This means that HCl uis in excess , hence excessive reagent.

Moles of HCl left unreacted :

= 0.030 mol - 0.020 mol = 0.010 mol

But in the option moles of HCl left are 0.100 moles which is wrong, making the option incorrect.

answer; /// i do believe that the correct answer is (c)nuclear bond

20 drops hope this