Rank from the greatest to the least 1.43*10^6, 5.17*10^2, 2.34*10^5, 3.25*10^4, 4.56*10^3

1.43×10⁶ > 2.34×10⁵> 3.25×10⁴>4.56×10³> 5.17×10²

Explanation:

First of all we will write these values in simple notation.

1) 1.43×10⁶

1.43×1000000

1430000

2) 5.17×10²

5.17×100

517

3) 2.34×10⁵

2.34×100000

234000

4) 3.25×10⁴

3.25×10000

32500

5) 4.56×10³

4.56×1000

4560

Rank from greatest to least.

1.43×10⁶ > 2.34×10⁵> 3.25×10⁴>4.56×10³> 5.17×10²

the answer is c i believe

when 25.0 ml of 0.700 mol/l naoh was mixed in a calorimeter with 25.0 ml of 0.700 mol/l hcl, both initially at 20.0 °c, the temperature increased to 22.1 °c. the heat capacity of the calorimeter is 279 j/°c.

the equation for the reaction is:

naoh + hcl → nacl + h₂o

moles of hcl = 0.0250 l hcl ×

0.700

mol hcl

1 l hcl = 0.0175 mol hcl

volume of solution = (25.0 + 25.0) ml = 50.0 ml

mass of solution = 50.0 ml soln ×

1.00

ml soln

= 50.0 g soln

δt=t2-t1

= (22.1 – 20.0) °c = 2.1 °c

the heats involved are

heat from neutralization + heat to warm solution + heat to warm calorimeter = 0

q1+q2+q3=0

nδh+mcδt+cδt=0

0.0175 mol ×

δh

+ 50.0 g × 4.184 j·g⁻¹°c⁻¹ × 2.1 °c + 279 j°c⁻¹ × 2.1 °c = 0

0.0175 mol ×

δh

+ 439.32 j + 585.9 j = 0

0.0175 mol ×

δh

= -1025.22 j

δh=1025.22j0.0175 mol= -58 600 j/mol = -58.6 kj/mol