What mass of oxygen gas is produced by the reaction of 3.8 g of ammonium perchlorate?

There is 1.29 grams of O2 produced.

Explanation:

Step 1: Data given

Mass of ammonium perchlorate 3.8 grams

Molar mass of ammonium perchlorate = 117.49 g/mol

Step 2: The balanced equation

4NH4ClO4 → 5O2 + 6H2O + 2N2 + 4HCl

Step 3: Calculate moles of NH4ClO4

Moles NH4ClO4 = mass NH4ClO4 / molar mass NH4ClO4

Moles NH4ClO4 = 3.80 grams / 117.49 g/mol

Moles NH4ClO4 = 0.0323 moles

Step 4: Calculate moles of O2

For 4 moles of ammonium perchlorate consumed, we produce 5 moles O2, 6 moles H2O, 2 moles N2 and 4 moles HCl

For 0.0323 moles NH4ClO4 we'll have 5/4 * 0.0323 = 0.040375 moles of O2

Step 5: Calculate mass of O2

Mass O2 = moles O2 * molar mass O2

Mass O2 = 0.040375 moles * 32 g/mol

Mass O2 = 1.29 grams

There is 1.29 grams of O2 produced.

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