In millikan’s experiment, the oil droplets acquire one or more negative charges by combining with the negative charges that are produced from the ionization of air by x rays. by measuring the charges on the oil droplets, he calculated the charge on a single electron as −1.60×10−19 c. the charge on any negatively charged oil droplet is always a whole-number multiple of the fundamental charge of a single electron. if millikan was measuring the charge on an oil droplet with 4 negatively charged electrons on it, what charge would he have measured on the droplet?

-6.4x10⁻¹⁹ C

Explanation:

The elementary charge of one electron is -1.60x10⁻¹⁹C, so each electron has its charge, and a sample with more than one electrons will have a multiple of its charge, which is proportional to the number of electrons. So, if the oil droplet had 4 electrons, thus the charge will be four times the elementary charge:

4*(-1.60x10⁻¹⁹) C = -6.4x10⁻¹⁹ C

why do the isotopes of a particular element behave differently in nuclear reactions but the same in chemical reactions? chemical reactions involve changes to electrons in an atom; isotopes do not differ in electrons, and so they react the same way during chemical changes.