At a certain temperature the vapor pressure of pure heptane is measured to be . suppose a solution is prepared by mixing of heptane and of acetyl bromide .

This is an incomplete question, here is a complete question.

At a certain temperature the vapor pressure of pure heptane is measured to be 170 torr. Suppose a solution is prepared by mixing 86.7 g of heptane and 125 g of acetyl bromide.

Calculate the partial pressure of heptane above this solution. Round your answer to 3 significant digits.

Answer : The partial pressure of heptane is, 78.2 torr

Explanation : Given,

Mass of heptane = 86.7 g

Mass of acetyl bromide = 125 g

Molar mass of heptane = 100 g/mole

Molar mass of acetyl bromide = 122.9 g/mole

First we have to calculate the moles of heptane and acetyl bromide.

and

Now we have to calculate the mole fraction of heptane and acetyl bromide.

and

Now we have to partial pressure of heptane.

where,

= partial pressure of heptane

= total pressure of gas

= mole fraction of heptane

Therefore, the partial pressure of heptane is, 78.2 torr

im pretty sure its b

answer : one can design an experiment using a liquid and an additive that can be added to the liquid and observe the chemical changes in the reaction species.

one would need a beaker which is filled with a known amount of the liquid in which thermometer is placed to measure the temperature changes; after addition of the additive to the liquid solution one can note down the temperature change and find whether the reaction is endothermic or exothermic in nature. by subtracting the initial temperature value with the final temperature one can find the temperature changes.

various combinations of liquid and additive can be used. liquid in this case can be a known quantity of water and additives can be epsom salt or without epsom salt the experiment can be conducted to notice the changes. water and ice, hydrogen peroxide and dry yeast, vinegar and baking soda,etc.