Chemistry, 21.01.2020 04:31 Fire1099

What is the boiling point of a solution containing 0.144 g of eugenol dissolved in 10.0 g of benzene

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Answer from: kamand10

The boiling point of solution is 80.32°C

Explanation:

To calculate the molality of solution, we use the equation:

$\text{Molality of the solution}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}$

Where,

$m_{solute}$ = Given mass of solute (eugenol) = 0.144 g

$M_{solute}$ = Molar mass of solute (eugenol) = 164.2 g/mol

$W_{solvent}$ = Mass of solvent (benzene) = 10.0 g

Putting values in above equation, we get:

$\text{Molality of eugenol}=\frac{0.144\times 1000}{164.2\times 10.0}\\\\\text{Molality of eugenol}=0.088m$

To calculate the elevation in boiling point, we use the equation:

$\Delta T_b=iK_bm$

where,

$\Delta T_b$ = elevation in boiling point = $\text{Boiling point of solution}-\text{Boiling point of pure solution}$

Boiling point of pure solution (benzene) = 80.1°C

i = Vant hoff factor = 1 (For non-electrolytes)

K_b = molal boiling point elevation constant = 2.53°C/m

m = molality of solute = 0.088 m

Putting values in above equation, we get:

$\text{Boiling point of solution}-80.1=1\times 2.53^oC/m\times 0.088m\\\\\text{Boiling point of solution}=0.22+80.1=80.32^oC$

Hence, the boiling point of solution is 80.32°C

Answer from: Quest

explanation:

metals have excess of electrons whereas non-metals have deficiency of electrons. thus, in order to gain stability metals easily donate their electrons to the non-metals.

for example, electronic configuration of sodium is $1s^{2}2s^{2}2p^{6}3s^{1}$ and electronic configuration of phosphorous is $1s^{2}2s^{2}2p^{6}3s^{2}3p^{3}$ .

when a phosphorous atom and sodium atom combine together then sodium will donate is extra one electron to the phosphorous atom. as a result there will be formation of ionic bond between sodium and phosphorous.

the reaction will be as follows.

$3na + p \rightarrow na_{3}p$

there, are three sodium sodium atoms and each of them will donate its one extra electron to phosphorous atom. thus, the sub-shell of phosphorous gets completely filled.

thus, we can conclude that electrons are transferred from atoms of sodium to atoms of phosphorous. this transfer makes the sodium atoms donate one electron and the phosphorous atoms to gain one electron. as a result, the sodium and phosphorus atoms strongly attract each other.