1. determine the number of atoms in 4.64 g gold.

2. calculate the mass of 4.12 10e24 molecules of glucose (c6h12o6).

The answer to your question is below

Explanation:

1.-

a) Look for the mass number of Gold in the periodic table

Mass number = 197 g

Use proportions to answer this question

                          197 g of gold 6.023 x 10 ²³ atoms

                            4.64 g of gold  x

                            x = (4.64 x 6.023 x 10²³) / 197

                           x = 1.42 x 10²² atoms

2.- mass of 4.12 x 10²⁴ molecules of glucose

Molecular mass = (6 x 12) + (12 X 1) + (6 x 16)

                          = 72 + 12 + 96

                          = 180 g

             180 g of glucose 6.023 x 10 ²³ molecules

                x                          4.12 x 10 ²⁴ molecules

                x = (4.12 x 10²⁴ x 180) / 6.023 x 10²³

               x = 1231.3 g of glucose                  

the answer is c.the valence of the atoms combine .