In two or more complete sentences explain how to balance the chemical equation and classify its reaction type.
_h3po4 + __nabr __hbr + _na3po4

H₃PO₄ + 3NaBr   →    3HBr + Na₃PO₄

Double displacement reaction

Explanation:

Chemical equation:

H₃PO₄ + NaBr   →    HBr + Na₃PO₄

Balanced chemical equation:

H₃PO₄ + 3NaBr   →    3HBr + Na₃PO₄

Steps to balance:

H₃PO₄ + NaBr   →    HBr + Na₃PO₄

H = 3                           H = 1

P =  1                           P = 1

O =  4                          O = 4

Na =1                         Na = 3

Br =  1                        Br = 1

We will add the coefficient 3 with NaBr.

H₃PO₄ + 3NaBr   →    HBr + Na₃PO₄

H = 3                           H = 1

P =  1                           P = 1

O =  4                          O = 4

Na = 3                        Na = 3

Br =  3                        Br = 1

Now we will add the coefficient 3 with HBr.

H₃PO₄ + 3NaBr   →    3HBr + Na₃PO₄

H = 3                           H = 3

P =  1                           P = 1

O =  4                          O = 4

Na = 3                        Na = 3

Br =  3                        Br = 3

Now equation is completely balanced.

The reaction type is double displacement reaction.

Double replacement:

It is the reaction in which two compound exchange their ions and form new compounds.

AB + CD → AC +BD

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.