Asolution of methanol, ch3oh, in water is prepared by mixing together 128 g of methanol and 108 g of water. the mole fraction of methanol in the solution is closest to

Mole fraction of methanol = 0.4

Explanation:

Molar mass methanol: 32 g/mol

Molar mass water: 18 g/m

Mol = Mass / Molar mass

128 g / 32 g/m = 4 moles of CH₃OH

108 g / 18 g/m = 6 moles of H₂O

Mole fraction of methanol = Moles of methanol / Moles of methanol + Moles of H₂O

4 / 10 = 0.4

The mole fraction of methanol is  0.4

The molar mass of methanol is = 32 g/mol

The number of moles of methanol is = 128 g/32 g/mol = 4 moles

The molar mass of water is 18 g/mol

The number of moles of water = 108 g/18 g/mol = 6 moles

Total number of moles = 6 moles + 4 moles = 10 moles

Mole fraction of methanol = 4 moles/ 10 moles = 0.4

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1. 1 mole of anything contains 6.022x10^23 pieces  

d  

2. a  

3. c, number  

5. 1.24x10^24atoms / 6.022x10^23atoms/mole = 2moles h2 atoms  

6. fe2br3 mass = 2moles x mass fe + 3 moles x mass br  

molar mass = grams / number of moles = g/mole  

to find moles = g / molar mass  

to find mass = g = molar mass / moles

answer: -

reaction:

na + cl ⇌ nacl

balanced chemical equation:

na + 2cl ⇌ nacl2

sodium + clorine goes to form sodium chloride (table salt).

the product is nacl2.

and the reactants are na and cl.

(note: if you don’t know what ⇌ means, read below: -

⇌(double head arrow) means reversible reaction).