You dissolve 0.476 g of naoh in 2.00 l of a buffer solution that originally had [h2po4-] = [hpo42-]= 0.132 m. look up the ka value in your text. a. what is the ph of the buffer solution before addition of the sodium hydroxide? ph = b. what is the concentration of dihydrogen phosphate after addition of the sodium hydroxide? [h2po4-] = m c. what is the concentration of the hydrogen phosphate after addition of the sodium hydroxide? [hpo42-] = m d. what is the ph of the buffer solution after addition of the sodium hydroxide? ph =

the ratio of the conjugate base to the acid required to attain the desired ph.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied