Ametal hydroxide with the general formula m(oh)2 has a ksp value of 0.00037. calculate the molar solubility of this metal hydroxide.

The molar solubility of this metal hydroxide is 0.0452 mol/L

Explanation:

Step 1: Data given

General formula = M(OH)2

Ksp = 0.00037

Step 2: The balanced equation

M(OH)2 → M^2+ + 2OH-

Step 3: Calculate the molar solubility of this metal hydroxide.

If we have X of M(OH)2, it will completely react. So there will react X

For 1 mol M(OH)2 we have 1 mol M^2+ and 2 moles OH-

There will be formed X of M^2+ and 2X of OH-

Ksp = [M^2+]*[OH-]²

Ksp = 0.00037 =  X*(2X)² = 4X³

X = 0.0452

The molar solubility of this metal hydroxide is 0.0452 mol/L

it is called acid bonding