How many grams of iron can be obtained from a 268-g sample of iron(iii) oxide?

187.44 g

Explanation:

Calculation of the moles of as:-

Mass = 268 g

Molar mass of iron(III) oxide = 159.69 g/mol

The formula for the calculation of moles is shown below:

Thus,

According to the formula, 1 mole of iron(III) oxide has 2 moles of iron.

Also,

1.67825 mole of iron(III) oxide has moles of iron.

Moles of iron = 3.3565 moles

Molar mass of iron = 55.845 g/mol

Mass=Moles*Molar mass = = 187.44 g

187.44 g of iron can be obtained from a 268-g sample of iron(III) oxide.

c. 75.7

i think that is the right

they it depends on if one believes about radioactivity, they make a geiger counter beep but maybe it was going to beep anyway electronics do wierd things all the time or it was programmed to beep near certain metals.