Write a balanced chemical equation based on the following description: aqueous iron(iii) chloride reacts with aqueous ammonium sulfide to make aqueous ammonium chloride and solid iron(iii) sulfide

2FeCl3(aq) + 3(NH4)2S(aq) →6NH4Cl(aq) + Fe2S3(s)

Explanation:

Step 1: Data given

The reactants are:

iron(III) chloride = FeCl3

ammonium sulfide = (NH4)2S

The products are:

ammonium chloride = NH4Cl

iron(III) sulfide = Fe2S3

Step 2: Balance the reaction

FeCl3(aq) + (NH4)2S(aq) → NH4Cl(aq) + Fe2S3(s)

On the right side we have 2x Fe, so on the left side, to balance the amount of Fe on both sides, we should multiply FeCl3 by 2

2FeCl3(aq) + (NH4)2S(aq) → NH4Cl(aq) + Fe2S3(s)

On the left side we have 6x Cl, on the right side 1x Cl. To balance the amount of Cl we have to multiply NH4Cl (on the right side) by 6

2FeCl3(aq) + (NH4)2S(aq) →6NH4Cl(aq) + Fe2S3(s)

On the right side we have 6x NH4, on the left side we have 2x NH4. To balance this amount we should multiply (NH4)2S on the left side by 3

Now the reaction is balanced.

2FeCl3(aq) + 3(NH4)2S(aq) →6NH4Cl(aq) + Fe2S3(s)

The balanced equation for the reaction between aqueous iron(III) chloride and aqueous ammonium sulfide to produce aqueous ammonium chloride and solid iron(III) sulfide  is:

The equation for the reaction between aqueous iron(III) chloride and aqueous ammonium sulfide to produce aqueous ammonium chloride and solid iron(III) sulfide can be written as follow:

Iron (III) chloride => FeCl₃

Ammonium sulfide => (NH₄)₂S

Ammonium chloride => NH₄Cl

Iron(III) sulfide => Fe₂S₃

Iron (III) chloride + Ammonium sulfide —> Ammonium chloride + Iron(III) sulfide

FeCl₃ + (NH₄)₂S —> NH₄Cl + Fe₂S₃

The above equation can be balance as follow:

FeCl₃ + (NH₄)₂S —> NH₄Cl + Fe₂S₃

There are 2 atoms of Fe on the right side and 1 atom on the left side. It can be balance by writing 2 before FeCl₃ as shown below:

2FeCl₃ + (NH₄)₂S —> NH₄Cl + Fe₂S₃

There are 3 atoms of S on the right side and 1 atom on the left side. It can be balance by writing 3 before (NH₄)₂S as shown below:

2FeCl₃ + 3(NH₄)₂S —> NH₄Cl + Fe₂S₃

There are 6 atoms of Cl on the left side and 1 atom on the right side. It can be balance by writing 6 before NH₄Cl as shown below:

2FeCl₃ (aq) + 3(NH₄)₂S (aq) —> 6NH₄Cl (aq) + Fe₂S₃ (s)

Now, the equation is balanced!

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"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"

answer; talc and gypsum;