What volume of 3.00 m hcl will form a solution with a basic ph when mixed with 100 ml of 3.00 m naoh?

a)101 ml

b)100 ml

c)150 ml

d)50.0 ml

d)50.0 mL

Explanation:

At equivalence point ,

Moles of = Moles of NaOH

Considering :-

Given  that:

So,  

The volume of HCl at equivalence point is - 100 mL

More addition of the acid forms a acidic solution. Thus, d)50.0 mL is the correct option because all other options are greater or equal to 100 which leads to acidic or neutral solution respectively.

2fe + 3h2so4 -> fe2(so4)3 + 3h2

it is necessary to balance equations in order to get the proper amount of reactants as well as products in order not to make a miscalculation.

you cannot change the subscripts as that would change the substance itself. for instance, diatomic elements such as h2 only have the subscript two when a gas. another example would be so4, if you were to change the subscript, the element would no longer be sulfate.

we change the coefficients instead as that only changes the number of molecules rather than the substance itself.

hope this !