Calculate the temperatureoc that 0.2 moles of gas in a
balloon at 2.0 atmoccupies 2.0 l.

- 29.54 °C

Explanation:

Given that:-

Pressure = 2.0 atm

Volume = 2.0 L

n = 0.2 mol

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

2.0 atm × 2.0 L = 0.2 mol × 0.0821 L.atm/K.mol × T

⇒T = 243.61 K

The conversion of T(K) to T( °C) is shown below:

T( °C) = T(K) - 273.15  

So,  

T = (243.61 - 273.15) K = - 29.54 °C

- 29.54 °C is the temperature.

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