Caluclate the number of grams of oxygen that must react
with46.85g of c3h 8 to produce only carbondioxide
and water.

Answer : The number of grams of oxygen react must be, 170.4 grams.

Solution : Given,

Mass of = 46.85 g

Molar mass of = 44 g/mole

Molar mass of = 32 g/mole

First we have to calculate the moles of .

Now we have to calculate the moles of

The balanced chemical reaction is,

From the balanced reaction we conclude that

As, 1 mole of react with 5 mole of

So, 1.065 moles of react with moles of

Now we have to calculate the mass of

Therefore, the number of grams of oxygen react must be, 170.4 grams.