What is the ph of a solution in which the [oh-] =
1x 10-5?

the pH of the solution = 9

Explanation:

pH -

The value of pH is used to determine the acidic strength of the solution , depending on the connection of the H⁺ ions in the solution.

pH is given as negative log of the H⁺ concentration.

Since,

pH = - log [ H⁺ ]

Similarly ,

pOH = - log [ OH⁻ ]

The relation between pH and pOH is -

pH + pOH = 14

From the question,  

[OH⁻] =  1 * 10⁻⁵

pOH = - log [ OH⁻ ]

pOH = - log [ 1 * 10⁻⁵ ]

pOH = 5

Therefore,

pH + pOH = 14

pH + 5 = 14

pH = 9

Hence, the pH of the solution = 9

it is stable as it is in group 0 which have full outer shells of electrons