The molar heats of fusion and sublimation of molecular
iodineare 15.27 kj/mol and 62.30 kj/mol, respectively. estimate the
molarheat of vaporization of liquid iodine.

47.03 KJ/mol

Explanation:

given:

molar heat of fusion, Hfusion = 15.27 KJ/mol

molar heat of sublimation, Hsublime = 62.30 KJ/mol

molar heat of vaporisation, Hvaporise = ?

Hsublime = Hfusion + Hvaporise

Hvaporise = Hsublime - Hfusion

Hence, the molar heat of vaporization of liquid iodine

= 62.30 - 15.27 = 47.03 KJ/mol

c. because step up transformer steps up the input voltage i.e increases the input voltage  

the number of turns are greater on the secondary side of step up transformer  

transformer does not handle dc current

i think it's c. if you look search electronic symbol on google and then click on wiki it shows you a