What mass of cdp (403 g mol−1) is in 10 ml of the buffered solution at the beginning of experiment 1? 6.4 × 10−4 g 6.4 × 10−3 g 6.4 × 10−2 g 6.4 × 10−1 g

Compete Question:

What mass of CDP (403 g mol−1) is in 10 mL of the buffered solution at the beginning of Experiment 1?

               Passage: "16 mmol of CDP in 1 L of buffer"

6.4 × 10-2 g  

Explanation:

   we are given from the question that 16 mmol of CDP is in 1 L of buffer

    this mean that we have moles of CDP in 1 liter of buffer.

so the mass of CDP in one liter of buffer will be calculate as,

         mass of CDP = × 403g mol−1

                               =

                               = 6.4 g/L

But because the question

asks us about the mass of CDP in 10 mL of solution, we will go further to calculate it like this:

6.4 g/L × 10 mL

6.4 g/L × 0.01 L  =

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