16. what is the density of lead if a cube measuring 2 cm per side has a mass of 90.8 g?

The density of lead if cube measuring 2 cm per side has a mass of 90.8 g is 11.35 g/cm^3

Explanation:

Density is equal to mass is divided by volume.

It is given that mass of 90.8 grams

we can find the volume of cube by height multiplied by width multiplied by depth.

Because all sides of cube are of same length.

Volume just ends up being 2^3

(2 cm)^3 = 8 cm ^3

Now plug both of these numbers into density equation

ρ =m/v

=90.8 g / 8 cm ^3

=11.35 g/cm^3

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.