16. what is the density of lead if a cube measuring 2 cm per side has a mass of 90.8 g?

The density of lead if cube measuring 2 cm per side has a mass of 90.8 g is 11.35 g/cm^3

Explanation:

Density is equal to mass is divided by volume.

It is given that mass of 90.8 grams

we can find the volume of cube by height multiplied by width multiplied by depth.

Because all sides of cube are of same length.

Volume just ends up being 2^3

(2 cm)^3 = 8 cm ^3

Now plug both of these numbers into density equation

ρ =m/v

=90.8 g / 8 cm ^3

=11.35 g/cm^3

radioactive decay occurs in unstable atomic nuclei – that is, ones that don't have enough binding energy to hold

the nucleus together due to an excess of either protons or neutrons.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml