As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm. (a) determine the air pressure. (b) if the mercury in the barometer is replaced with water, using the pressure you found in (a), to what height will the water level rise?

The air pressure is 9.8 *10^4 pa

The water will rise to a height of 10.0 meter

Explanation:

Step 1: Data given

As a storm from moves in, you notice that a column of mercury in a barometer rises to 736 mm.

Step 2: Calculate the air pressure

The Pressure against the mercury column = h*d*g = 0.736 * 13593 * 9.81 = 9.8 * 10^4 Pa

Step 3: Calculate the height of the water

Let the Pressure  the water column for same pressure is h meter : -

9.8 * 10^4 = h*d*g  

=>9.8*10^4 = h*1000*9.81  

=>h = 10.0 meter

The water will rise to a height of 10.0 meter

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.