Oxygen gas, generated by the reaction 2 kclo 3 2 kcl + 3 o 2 , is collected over water at 27 c in a 2.00 l vessel at a total pressure of 760. mmhg. the vapor pressure of h 2 o at 27 c is 26 mmhg. how many moles of kclo 3 were consumed in the reaction?

The moles of KClO3 = 0.052 moles

Explanation:

Step 1: Calculate the pressure of oxygen gas

The oxygen has a total pressure (including water vapour) of 760 mmHg

The pressure of Oxygen = (760 - 26) mmHg

                                         = 734 mmHg of water vapor

Step 2: Calculate the no of moles of oxygen

        Using Ideal gas equation

        P V = n R T

       P = pressure of oxygen in N/m2 ( you should convert 734 mmHg to pascal or N/m2) = 97,858.6 N/m2 or pas

       V = 2 litres = 0.002 m3

       R = gas constant = 8.31

       T= 27oC = 300 K

Applying this equation P V = n R T

        97,858.6 x 0.002 = n x 8.31 x 300

        n = 0.0785 mol of Oxygen

From the balanced equation

2 KClO 3 2 KCl + 3 O 2

3 moles of oxygen is produced from 2 moles KClO3

so 0.0785 mole of oxygen will be produced from x

x = (0.0785 x 2 ) / 3

x = 0.052 moles of KClO3

mechanics (greek   is that area of science concerned with the behaviour of physical bodies when subjected to forces or displacements, and the subsequent effects of the bodies on their environment. the scientific discipline has its origins in ancient greece with the writings of aristotle and archimedes[1][2][3] (see history of classical mechanics and timeline of classical mechanics). during the early modern period, scientists such as galileo, kepler, and newton laid the foundation for what is now known as classical mechanics. it is a branch of classical physics that deals with particles that are either at rest or are moving with velocities significantly less than the speed of light. it can also be defined as a branch of science which deals with the motion of and forces on objects. the field is yet less widely understood in terms of quantum theory.

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