The relative humidity of air equals the ratio of the partial pressure of water in the air to the equilibrium vapor pressure of water at the same temperature, times 100%.% and its temperature is 68 of , how many moles of water are present in a room measuring 12 ft x 10 ft x 8 ft?

Question:

The relative humidity of air equals the ratio of the partial pressure of water in the air to the equilibrium vapor pressure of water at the same temperature times 100%. If the relative humidity of the air is 58% and its temperature is 68 oF , how many moles of water are present in a room measuring 12 ft x 10 ft x 8 ft?

15.1379 moles  of water are present in a room measuring 12 ft x 10 ft x 8 ft.

Explanation:

Given:

Relative humidity of the air = 58%

Temperature =

To Find:

Number of moles of water are present in a room measuring 12 ft x 10 ft x 8 ft = ?

Solution:

Converting temperature Fahrenheit to Celsius

The vapour pressure of is equal to 17.54 torr

vapour pressure of air

= torr

= 10.17132 torr

Volume of the room =

=>

=>

Using the ideal gas equation

PV = nRT

Volume in Litres = 27184.2 L

Pressure in atm

=

= 0.0133945 atm

Now substituting the values we get

Pv = nRT

n = 15.1379 moles

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