Asample contains 6.73 g of na2co3 in water to make a total of 250.0 ml of solution. what is the molarity of sodium carbonate in this solution and its mass-% ? use 1.00 g/ml as the density of the solution.

Molarity of Na₂CO₃ = 0.25M

% mass = 2.69

Explanation:

Molarity means mole of solute in 1L of solution

Molar mass of solute (Na₂CO₃) = 105,98 g/m

Moles = mass / molar mass → 6.73 g / 105.98 g/m = 0.0635 m

Mol/L = [M]

0.0635 mol/0.250L = 0.25M

Density of solution = Solution mass / Solution volume

1 g/ml = Solution mass / 250 mL → Solution mass is 250g

% mass will be:

In 250 g of solution we have 6.73 g of solute

in 100 g of solution we have (100 . 6.73)/250 = 2.69

The molarity of Na2CO3 in the solution = 0.254 M

The mass % of Na2CO3 is 2.69 %

Explanation:

Step 1: Data given

Mass of Na2CO3 = 6.73 grams

Volume of the solution = 250.0 mL

Density = 1.00g/mL

Molar mass of Na2CO3 = 105.99 g/mol

Step 2: Calculate moles of Na2CO3

Moles Na2CO3 = 6.73 grams / 105.99 g/mol

Moles Na2CO3 = 0.0635 moles

Step 3: Calculate molarity of Na2CO3

Molarity = moles / volume

Molarity = 0.0635 moles / 0.250 L

Molarity = 0.254 M

Step 4: Calculate mass of the solution

Mass = volume * density

Mass = 250 mL * 1.00g/mL

Mass = 250 grams

Step 5: Calculate mass %

mass% = (6.73 g / 250 g)*100%

mass % =  2.69 %

The mass % of Na2CO3 is 2.69 %

sodium (na), for example, has one electron in its valence shell. this is an unstable state because that valence shell needs eight electrons to be full. in order to fill its valence shell, find a way to add seven electrons to its valence shell

- "the acute form of diverticulitis can manifest itself with one or more severe attacks of infection and inflammation.

the inflammation of diverticulitis can eventually result in a bowel obstruction, which may cause constipation, thin stools, diarrhea, abdominal swelling or bloating, and abdominal pain."