Chemistry, 28.12.2019 05:31 lisamiller
Calculate horxn for the following reaction: h3aso4(aq) + 4 h2(g) --> ash3(g) + 4 h2o(l)(hof [ash3(g)] = 66.4 kj/mol; hof [h3aso4(aq)] = -904.6 kj/mol; hof [h2o(l)] = -285.8 kj/mol)
Answers: 3
![\Delta H_{f}^{\circ } [H_{3}AsO_{4}(aq)]](/tpl/images/0435/4880/bc889.png)
= -904.6 kJ/mol![\Delta H_{f}^{\circ } [H_{2}(g)]](/tpl/images/0435/4880/b83d7.png)
= 0 kJ/mol,![\Delta H_{f}^{\circ } [AsH_{3}(g)]](/tpl/images/0435/4880/eaaf4.png)
= +66.4 kJ/mol![\Delta H_{f}^{\circ } [H_{2}O(l)]](/tpl/images/0435/4880/46f61.png)
= -285.8 kJ/mol 
= ?
![\Delta H_{r}^{\circ } = [1 \times \Delta H_{f}^{\circ } [AsH_{3} (g)] + 4 \times \Delta H_{f}^{\circ } [H_{2}O(l)]] - [1 \times \Delta H_{f}^{\circ } [H_{3}AsO_{4}(aq)] + 4 \times \Delta H_{f}^{\circ } [H_{2}(g)]](/tpl/images/0435/4880/cee8f.png)
![\Rightarrow \Delta H_{r}^{\circ } = [1 \times (+66.4\,kJ/mol) + 4 \times (-285.8\,kJ/mol) ] - [1 \times (-904.6\,kJ/mol) + 4 \times (0\,kJ/mol)]](/tpl/images/0435/4880/49bdc.png)
![\Rightarrow \Delta H_{r}^{\circ } = [-1076.8\, kJ] - [-904.6\,kJ]](/tpl/images/0435/4880/a7183.png)
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Calculate horxn for the following reaction: h3aso4(aq) + 4 h2(g) --> ash3(g) + 4 h2o(l)(hof [a...
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