We find that 18.90 milliliters of a 2.50m koh solution are required to titrate 35.0 milliters of a h2s04 solution. what is the molarity of the h2s04 solution? 2 2koh + h2s04 k2s04 2 h20 a. 0.675 m b. 1.57 m c. 0.0711 m d. 0.128 m e. 4.04 m f. 0.903 m g. 1.18 m h. 0.0173 m

Concentration of is 0.675 M

Explanation:

According to balanced equation, 2 moles of KOH neutralizes 1 mol of .

18.90 mL of 2.50M KOH = of KOH = 0.04725 moles of KOH

If molarity of is C (M) then-

moles of are neutralized =   of

Hence,

or, C = 0.675

So, concentration of is 0.675 M

oh it is true if thats what you are asking