When heated up with propanoyl chloride, which of the following nitrogen-cont compounds would not result in an amide? a. triethylamine b. aniline c. dibutylamine d. methylamine e. ammonia

Option A is correct. A tertiary amine will not form an amide with acyl chlorides they can only transform acyl chlorides into ketenes.

Explanation:

(a). Reaction of acyl chloride with aniline: Aniline is the simplest primary amine. The -NH2 group is attached directly to the benzene ring. The equation of reaction is given below;

CH3COCl + 2C6H5NH2> CH3CONHC6H5 +C6H5NH3Cl.

The products of the reaction are The products are N-phenylethanamide,C6H5NH2 and phenylammonium chloride, C6H5NHCl.

(b). Reaction of acyl chloride with primary and secondary amine:

The -NH2 is attached to an alkyl group for the primary and secondary amine. Typical reaction equation for a primary amine with acyl chloride is given below;

CH3COCl + CH3NH2> CH3CONHCH3 + HCl.

The HCl will further react with NH3 to produce The salt is called methylammonium chloride.

(c). Reaction of acyl chloride with amine: the equation of reaction is given below;

CH3COCl + NH3 > CH3CONH2 + HCl.

The hydrogen chloride produced reacts with excess ammonia to form ammonium chloride;

NH3 + HCl > NH4Cl.

particle   p is an electron and particle q is a neutron

fe 55.85 g/mol and h2o 18.02 g/mol.