Solid sodium hydroxide decomposes into solid sodium oxide and gaseous water . write a balanced chemical equation for this reaction.

2 NaOH(s) → Na2O(s) + H2O(g)

Explanation:

Step 1: Data given

Solid sodium hydroxide decomposes into solid sodium oxide and gaseous water

Step 2: The balanced equation

NaOH(s) → Na2O(s) + H2O(g)

On the right side we have 2 times Na, so on the left side we have to multiply NaOH by 2. Now we have 2x Na on both sides.

2 NaOH(s) → Na2O(s) + H2O(g)

Now on both sides we have 2x Na, 2x O and 2x H

The equation is balanced.

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.