Calculate the nuclear binding energy in mega-electronvolts (mev) per nucleon for 136 ba . 136 ba has a nuclear mass of 135.905 amu . nuclear binding energy per nucleon:

8.194 Mev per nucleon

Explanation:

Mass of Barium = 135.905 amu

number of proton = 56, number of neutron = 80

Md = (Mp + Mn) - Mb Mp is the mass of proton, Mn is the mass of neutron, Mb is the mass of barium and Md is the mass defect

Mn = 1.00867 amu Mp = 1.00728 amu

Md = ( 56 ( 1.00728) + 80 ( 1.00867) = 137.1013 - 135.905 =1.1963 amu

Md = 1.1963 × 1 ÷ ( 6.02214 × 10 ²⁶ amu ) = 1.9865 × 10 ⁻²⁷ kg

Energy = mc² = 1.9865 × 10 ⁻²⁷ kg × (2.99792 × 10 ⁸ m/s)²

E= 1.78537 × 10⁻¹⁰ J

to convert to Mev

1.78537 × 10⁻¹⁰ × 6241457006000 = 1114.33 Mev

binding energy per nucleon = 1114.33 / 136 =8.194 Mev per nucleon

idk i’m struggling too