The vapour pressure of pure benzene at 20 °c is 75 torr and that of pure methylbenzene is 25 torr at the same tempera-ture. in an equimolar mixture xbenzene = xmethylbenzene = 1 so the 2 partial vapour pressure of each one in the mixture

Benzene: 37.5 Torr

Methylbenzene: 12.5 Torr

Explanation:

By Raoult's Law, each substance in a gas mixture contributes to the total pressure of the mixture proportionally to their respective mole fraction. So,

Ppartial = x*P°

Where x is the mole fraction (0.5 for each one because it's equimolar), and P° is the vapor pressure.

Benzene: Ppartial = 0.5 * 75 = 37.5 Torr

Methylbenzene: Ppartial = 0.5 * 25 = 12.5 Torr

16

explanation:

the marks go by 4s

i think its 5049.

i hope this !