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what is the volume of 3.6 mol nh3 at stp

80.64 Litres

Explanation:

At standard temperature and pressure conditions (STP),

1 mole of any gaseous substance occupies 22.4 L.

Hence 3.6 moles of gas occupies = 3.6*22.4 Litres

                                                          = 80.64 Litres.

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.

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