How many grams would 3.36 × 1023 molecules of copper (ii) sulfate (cuso4) weigh?

Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g 6.02 x 10²³ molecules
         ? g 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!

So what you would do is go through and add 3 teaspoons(tsp) 6 times because of the 6 tablespoons(tbsp). which will give you an answer of 18. another way is to multiply 3x6=18.