Water’s heat of vaporization is 2,257 joules/gram. how much energy is released when 11.2 grams of water vapor condenses into liquid?

25278.4 j

Explanation:

Given data:

Heat of vaporization of water = 2257 j/g

Energy released by converting 11.2 g water to liquid = ?

Solution:

The heat of vaporization of water is = 2257 j/g

It means one gram of water when converted into vapors 2257 j heat is involved.

For 11.2 grams of water when  converted into liquid energy released would be:

11.2 g× 2257 j/g

25278.4 j

number of molecules / avogadro's number * molecule molecular = mass

explanation:

we define a gram-molecular weight as the mass of one mole of any element or compound. a mole contains avogadro's number of units (molecules) –  

6.022

x

10

23

. so, dividing the number of molecules by avogadro's number gives us the number of moles. multiplying that by the molecular weight gives us the mass. from the periodic table we find the gram-molecular weight of u to be238 and of f to be19. so,  

u

f

6

will have a gram-molecular weight of 352g.