The solubility of oxygen in lakes high in the rocky mountains is affected by the altitude. if the solubility of o 2 from the air is 2.67 × 10 –4 m at sea level and 25°c, what is the solubility of o 2 at an elevation of 12,000 ft where the atmospheric pressure is 0.657 atm?

assume the temperature is 25°c, and that the mole fraction of o 2 in air is 0.209 at both 12,000 ft and at sea level. 1.75 × 10–4 m 2.67 × 10–4 m 3.66 × 10–5 m 4.06 × 10–4 m

S = 1,75x10⁻⁴M

Explanation:

It is possible to answer this question using Henry's law that states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid. The formula is:

S = k×Pi

Where S is solubility, K is Henry's constant and Pi is partial pressure.

At sea level, Pi of O₂ is:

1atm×0,209 = 0,209 atm. Replacing:

2,67x10⁻⁴M = k×0,209atm

k = 1,28x10⁻³M/atm

At 12,000ft Pi of O₂ is:

0,657atm×0,209 = 0,137 atm. Replacing:

S = 1,28x10⁻³M/atm×0,137atm

S = 1,75x10⁻⁴M

I hope it helps!

the child will have heterozygous dominant chromosomes as characters of his father are dominant over the characters of his mother.

the child is heterozygous

the answer would be c